2x^2-7=5x-16

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Solution for 2x^2-7=5x-16 equation: 



2x^2-7=5x-16

We move all terms to the left:

2x^2-7-(5x-16)=0

We get rid of parentheses

2x^2-5x+16-7=0

We add all the numbers together, and all the variables

2x^2-5x+9=0

a = 2; b = -5; c = +9;
Δ = b2-4ac
Δ = -52-4·2·9
Δ = -47
Delta is less than zero, so there is no solution for the equation

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